Solve for x if log2+log(x+3)-log(3x-5)=log3
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log2+log(x+3)-log(3x-5)=log3
= 2*(x+3)/(3x-5)=3
= 2x+6=9x-15
=7x=21
=x=3
= 2*(x+3)/(3x-5)=3
= 2x+6=9x-15
=7x=21
=x=3
Answered by
11
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