Solve for x if log2 log2 logx 6561 = 2 and x > 0.
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Answer:Using the definition of logarithm,
if logₐx = n, then x = aⁿ
Consider log₃[log₂(log₃x)] = 1
So by definition of logarithm
[log₂(log₃x)] = 3¹
log₂(log₃x) = 3
So by definition of logarithm
log₃x = 2³
log₃x = 8
So by definition of logarithm
x = 3⁸
x = 6561
Hence, Proved !
Hope, it helps !
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