SOLVE for x if mode x+3=-6
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Answered by
0
lx+3l = -6
here we will get two cases
case(1)
(x+3) = -6
x = -6-3
x = -9
case(2)
-(x+3)=-6
x+3=6
x=6-3
x=3
so,
x=-9 and 3
here we will get two cases
case(1)
(x+3) = -6
x = -6-3
x = -9
case(2)
-(x+3)=-6
x+3=6
x=6-3
x=3
so,
x=-9 and 3
Answered by
0
|x+3|=-6
in mod if negative integers are there then they will be become positive if positive then also the same
x+3=-6
x=-9
in mod if negative integers are there then they will be become positive if positive then also the same
x+3=-6
x=-9
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