Question

Solve for x. If x^2-3x-28/x^2-49=3/17,x not equal to +-7

Answer 1

Step-by-step explanation:

consider

•(x^2-3x-28)/(x^2-49)=(3/17)

•(x^2-7x+4x-28)/(x^2-7^2)=(3/17)

we have to use (a^2-b^2)=(a-b)(a+b)

•[ x(x-7)+4(x-7) ] / [ (x-7)(x+7) ]=(3/17)

•[ (x+4)(x-7)] / [ (x-7)(x+7) ]=(3/17)

•(x+4)/(x+7)=(3/17)

•17(x+4)=3(x+7)

•17x+68=3x+21

•17x-3x = -68+21

•14x = -47

• x = -(47/14)