Question

Solve for x if x^2+(ax/a+x)^2=3a^2 if x
id not =-a

Answer 1

Hey 

[tex] x^{2} + (\frac{ax}{a+x})^2 = 3a^2 \\ \\ (a+x)^2x^2 + (ax)^2 = 3a^2(a+x)^2 \\ \\ a^2x^2 + x^4 + 2ax^3 + a^2x^2 = 3a^4 + 6a^3x+ 3a^2x^2 \\ \\ x^4 - 3a^4 + 2ax^3 - 6a^3x - a^2x^2 = 0 \\ \\ -(a^2 + ax - x^2 )( 3a^2 + 3ax + x^2 ) = 0[/tex]

Now, you find the root of the two Quadratics -->
( a² + ax - x² ) = 0   ||     ( 3a² + 3ax + x² ) = 0

We also see that ( 3a² + 3ax + x² ) = 0 has no real roots

=> a² + ax - x² = 0 <---- is the only quadratic ...

Solve it and have ur answer ^_^

Answer 2

Answer:

Ye Jo highlight kia h vo kese aaya

please explain by step

I will thank you and rate 5 stars ✳️