Question

solve for x in the equation 8x^2-2x-3=0​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$\implies x = \frac{3}{4} \: Or \: x= \frac{-1}{2}$

Step-by-step explanation:

$8x^{2} - 2x - 3 = 0$

$\implies 8x^{2} - 6x + 4x - 3 = 0$

$\implies 2x(4x - 3) + 1(4x-3) = 0$

$\implies (4x-3)(2x+1) = 0$

$\implies 4x - 3 = 0 \: Or \: 2x+1 = 0$

$\implies 4x = 3 \: Or \: 2x= -1$

$\implies x = \frac{3}{4} \: Or \: x= \frac{-1}{2}$

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