Question

solve for x in the given attachment​

Answer 1

Answer:

Step-by-step explanation:

x=2(a sq +b sq) +-root 2(asq+bsq)sq-4asqbsq*4

X=2(asq+bsq)+-root 4(asq)sq+(bsq)sq+2asqbsq-16asqbsq

X=2(asq+bsq)+-root (2asq)sq+(2bsq)sq+8asqbsq-16asbsq

X=2(asq+bsq)+-root(2asq-2bsq)sq

X=2asq+2bsq+-(2asq-2bsq)

X=2asq+2bsq+2asq-2bsq,=4asq/8=1/2asq

X=2asq+2bsq-2asq +2bsq, =4bsq /8=1/2bsq

X=1/2asq,1/2bsq

Answer 2

Answer:

Step-by-step explanation:

D=b²-4ac

={2(a²+b²)}²-4×4×a²b²

=4a⁴+4b⁴+8a²b²-16a²b²

=4a⁴+4b⁴-8a²b²

={2(a²-b²)}

X=-b±√D/2a

=-{-(2a²+2b²)}+2(a²-b²)/8

=2a²+2b²+2a²-2b²/8

=4a²/8

=a²/2

OR

=-{-(2a²+2b²)}-2(a²-b²)/8

=2a²+2b²-2a²+2b²/8

=4b²/8

=b²/2

HOPE IT HELPS YOU!!!!!!!!