Solve for x is belong to real no.
4^x-10.2^x-1=24
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Hi ,
4^x - 10 × 2^x-1 = 24
2^2x - 10 × ( 2^x/2 ) - 24 = 0
( 2^x )² - 5 × 2^x - 24 = 0
( 2^x )² - 8 × 2^x + 3 × 2^x - 24 = 0
2^x ( 2^x - 8 ) + 3 ( 2^x - 8 ) = 0
( 2^x - 8 ) ( 2^x + 3 ) = 0
Therefore ,
2^x - 8 = 0 or 2^x + 3 = 0
2^x = 8
2^x = 2³
x = 3
I hope this helps you.
: )
4^x - 10 × 2^x-1 = 24
2^2x - 10 × ( 2^x/2 ) - 24 = 0
( 2^x )² - 5 × 2^x - 24 = 0
( 2^x )² - 8 × 2^x + 3 × 2^x - 24 = 0
2^x ( 2^x - 8 ) + 3 ( 2^x - 8 ) = 0
( 2^x - 8 ) ( 2^x + 3 ) = 0
Therefore ,
2^x - 8 = 0 or 2^x + 3 = 0
2^x = 8
2^x = 2³
x = 3
I hope this helps you.
: )
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