Math, asked by aparnamenon12345, 1 month ago

solve for x
please answer​

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Answers

Answered by soumya1145
0

Answer:

x=1

Step-by-step explanation:

\sqrt{9^{2} } ^{2x+4} = \sqrt[2]{27^{2} }^{2x+2}

9^{2x+4} = 27^{2x+2}

3^{4x+8} = 3^{6x+6}

4x+8=6x+6

2=2x

x=1

Answered by Snehalghosh
0

Answer:

x = 1

Step-by-step explanation:

(\sqrt{8} )^{2x + 4} = ( \sqrt{729} )^{2x + 2} \\\\=> 9^{2x + 4} = 27^{2x + 2} \\\\=> ( 3^{2} )^{2x + 4} = ( 3^{3} )^{2x + 2} \\\\=> 3^{4x + 8} = 3^{6x + 6} \\\\=> 4x + 8 = 6x + 6                    [ Since the bases are same]\\=> 4x - 6x = 6 - 8\\=> -2x = -2\\=> x = 1

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