Question

( solve for X )
please help me to solve this​

Answer 1

Answer:

${ \cos}^{2} 30 \degree + { \sin }^{2} 2x = 1 -(i)\\ {( \frac{ \sqrt{3} }{2} )}^{2} + { \sin }^{2} 2x = 1 \\ \frac{3}{4} + { \sin }^{2} 2x = 1 \\ \sin2x = \sqrt{1 - \frac{3}{4} } =± \sqrt{ \frac{1}{4} } \\ \\ \sin2x = ± \frac{1}{2} \\ \blue{\mathfrak{\underline{\large{Put \: \sin2x = \frac{1}{2} \: in \: {eq}^{n} \: (i)}}}:} \\ \frac{3}{4} + \frac{1}{4} = 1 \\ 1 = 1. \: veified \\ \blue{\mathfrak{\underline{\large{Put \: \sin2x = - \frac{1}{2} \: in \: {eq}^{n} \: (i)}}}:} \\ \frac{3}{4} + \frac{1}{4} = 1 \\ 1 = 1.verified \\ \blue{\mathfrak{\large{ \rightarrow \: both \: the \: values \: satisfy }}} \\ \blue{\mathfrak{\large{the \: given \: equation }}} \\ \blue{\mathfrak{\large{ \therefore \: \sin2x = ± \frac{1}{2} }}} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$