solve for x..
![log_{4}(32) = x - 4 log_{4}(32) = x - 4](https://tex.z-dn.net/?f=+log_%7B4%7D%2832%29++%3D+x+-+4)
yashikant537:
13/2 right ans
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Answered by
1
4^x-4=32
2^2x-8=2^5
2x-8=5
2x=13
x=13/2
2^2x-8=2^5
2x-8=5
2x=13
x=13/2
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0
I think this is right.....
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and....if correct.....
please please mark as brainlist plzz
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