Question

Solve for x .......
${x}^{2} + 14x + 2 = 0$
​

Answer 1

Answer:

Hope it helps......✌✌

Answer 2

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

${x}^{2} + 14x + 2 = 0$

${b}^{2} - 4ac \\ = {14}^{2} - 4(1)(2) \\ = 196 - 8 \\ = 188$

By quadratic formula ;

$= \frac{ - b \binom{ + }{ - } \sqrt{ {b}^{2} - 4ac } }{2a} \\ = \frac{ - 14 \binom{ + }{ - } \sqrt{188} }{2} \\ = \frac{ - 14 \binom{ + }{ - }2 \sqrt{47} }{2} \\ \frac{ - 7 \binom{ + }{ - } \sqrt{47} }{1} \\ x = - 7 + \sqrt{47} \: \: and \: \: \: \: \: x = - 7 - \sqrt{47}$

✴HAPPY TO HELP