Question

solve for x .. $x^2+ 6x + 9$​

Answer 1

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

${x}^{2} + 6x + 9 = 0 \\ {x}^{2} + 3x + 3x + 9 = 0 \\ x(x + 3) + 3(x + 3) = 0 \\ (x + 3)(x + 3) = 0 \\ \\ x = - 3 \: \: \: and \: \: \: x = - 3$

✴HAPPY TO HELP

Answer 2

$Given \: x^{2} + 6x + 9 = 9 \\\implies x^{2} + 2\times x \times 3 + 3^{2} = 0\\\implies ( x + 3)^{2} = 0$

$\blue { ( By \: Algebraic \:Identity )}$

$\boxed {\pink { a^{2} + 2ab + b^{2} = ( a + b )^{2} }}$

$\implies x + 3 = 0 \: Or \: x + 3 = 0$

$\implies x = -3 \: Or \: x = -3$

Therefore.,

$\green { Value \: of \: x = -3 }$

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