Solve for x the equation ln (x - 1) + ln (2x - 1) = 2 ln (x + 1)
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Answered by
16
Hi ,
We know that ,
***********"***"**************
1 ) ln x + ln y = ln xy
2 ) n ln a = ln a^n
**************************
According to the problem given,
ln (x- 1 ) + ln ( 2x - 1 ) = 2 ln ( x + 1 )
ln ( x - 1 ) ( 2x - 1 ) = ln ( x + 1 )²
ln ( 2x² - 3x + 1 ) = ln ( x² + 2x + 1 )
Therefore
2x² -3x + 1 = x² + 2x + 1
2x² - 3x + 1 - x² - 2x - 1 = 0
x² - 5x = 0
x ( x - 5 ) = 0
x = 0 or x- 5 = 0
x= 0 or x = 5
I hope this helps you
:)
We know that ,
***********"***"**************
1 ) ln x + ln y = ln xy
2 ) n ln a = ln a^n
**************************
According to the problem given,
ln (x- 1 ) + ln ( 2x - 1 ) = 2 ln ( x + 1 )
ln ( x - 1 ) ( 2x - 1 ) = ln ( x + 1 )²
ln ( 2x² - 3x + 1 ) = ln ( x² + 2x + 1 )
Therefore
2x² -3x + 1 = x² + 2x + 1
2x² - 3x + 1 - x² - 2x - 1 = 0
x² - 5x = 0
x ( x - 5 ) = 0
x = 0 or x- 5 = 0
x= 0 or x = 5
I hope this helps you
:)
Answered by
0
Step-by-step explanation:
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