Question

Solve for x using quadratic equation 36x2-12a+(a2-b2)=0

Answer 1

Given: The correct equation is 36x² - 12ax + ( a² - b² ) = 0

To find: The value of x.

Solution:

• Now we have given the quadratic equation as:

                    36x² − 12ax + (a² − b²) = 0

• Now we can write it as:

                     36x² − 12ax + a² − b² = 0

                    (36x² − 12ax + a²) − b² = 0

• 36x² − 12ax + a² is a square of 6x − a.

                    (6x − a)² − b² = 0

• So now using the identity, (a - b)(a + b) = a² - b²

                    (6x − a)² − b² = (6x − a − b) (6x − a + b)

                    (6x − a − b) (6x − a + b)  = 0

                    (6x − a − b) = 0 or (6x − a + b)  = 0

                    6x = a + b or 6x = a - b

                    x = ( a + b ) / 6, x = ( a − b ) / 6

Answer:

           So the value of x is ( a + b ) / 6 or ( a − b ) / 6