Solve for 'x' using the QUADRATIC EQUATION.
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The given quadratic equation is x^2 - 5√5x + 30 = 0
x^2 - 5√5x + 30 = 0
The factors of 30 that add up to -5√5 are -3√5 and -2√5.
x^2 - 3√5x - 2√5x + 30 = 0
x(x - 3√5) - 2√5(x - 3√5) = 0
(x - 3√5)(x - 2√5) = 0
x - 3√5 = 0 OR. x - 2√5 = 0
x = 3√5. OR. x = 2√5
The value of x is 3 √5 and 2 √5.
x^2 - 5√5x + 30 = 0
The factors of 30 that add up to -5√5 are -3√5 and -2√5.
x^2 - 3√5x - 2√5x + 30 = 0
x(x - 3√5) - 2√5(x - 3√5) = 0
(x - 3√5)(x - 2√5) = 0
x - 3√5 = 0 OR. x - 2√5 = 0
x = 3√5. OR. x = 2√5
The value of x is 3 √5 and 2 √5.
MotianiKrish:
but i asked you to solve using the QUADRATIC FORMULA
Your question doesn't mention it
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