Math, asked by haroon2670, 1 year ago

Solve for x value 2x²-3x=1+2x√x²-3x

Answers

Answered by madhura41
4
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Here is u r Ans ➡


2x {}^{2}  - 3x = 1 + 2x \sqrt{x {}^{2} }  - 3x

 = 2x = 1 + 2x \times  |x|

 = 2x - 2x \times  |x|  = 1

 = 2x - 2x \times x = 1 \\ x \geqslant 0

 = 2x - 2x \times ( -  x) = 1 \\ x < 0

 = x =  \frac{ - 1 +  \sqrt{3} }{2}
 = x =  \frac{ - 1 -  \sqrt{3} }{2}


 = x < 0

 = x =  \frac{ - 1 -  \sqrt{3} }{2}

 = in \: decimal \: form \:  - 1.36603

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