solve for x..... x-1/x-2+x-3/x-4=3whole1/3
Answers
Answered by
8
Answer:
x-1/x-2 + x-3/x-4 = 3+1/3
(x-1)(x-4) + (x-3)(x-4) / (x-2)(x-4) = 10/3
3(x^2 - 5x + 4 + x^2 - 7x + 12) = 10(x^2 - 6x + 8)
3(2x^2 - 12x + 16) = 10x^2 - 60x + 80
6x^2 - 36x + 48 = 10x^2 - 60x + 80
4x^2 - 24x + 32 = 0
x^2 - 6x + 8 = 0
(x-4)(x-2)=0
or x = 2 and x=4
Hope this helps you !
Answered by
0
Answer:
Helle divide it it's very much easy
Similar questions