Math, asked by kgoelhld2006, 1 year ago

solve for x..... x-1/x-2+x-3/x-4=3whole1/3​

Answers

Answered by dhruvsh
8

Answer:

x-1/x-2 + x-3/x-4 = 3+1/3

(x-1)(x-4) + (x-3)(x-4) / (x-2)(x-4) = 10/3

3(x^2 - 5x + 4 + x^2 - 7x + 12) = 10(x^2 - 6x + 8)

3(2x^2 - 12x + 16) = 10x^2 - 60x + 80

6x^2 - 36x + 48 = 10x^2 - 60x + 80

4x^2 - 24x + 32 = 0

x^2 - 6x + 8 = 0

(x-4)(x-2)=0

or x = 2 and x=4

Hope this helps you !

Answered by neelbrahma70
0

Answer:

Helle divide it it's very much easy

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