Question

solve for x: x- (18/x)=6 using Sridhar Acharya Method​

Answer 1

$x - (18 \div x) = 6 \\ ({x}^{2} - 18) \div x = 6 \\ {x}^{2} - 18 = 6x \\ {x}^{2} - 6x - 18 = 0$

now sridhar acharya method is for solving quadratic equations

when

$a {x}^{2} + bx + c = 0$

then the roots or solutions of the equation are

$x = ( - b + \sqrt{ {b}^{2} - 4ac} ) \div 2a$

and

$x = ( - b - \sqrt{ {b}^{2} - 4ac} ) \div 2a$

so now in equation

${x}^{2} - 6x - 18 = 0$

a=1,b=-6 and c=-18

$x = ( - ( - 6) + \sqrt{ { - 6}^{2} - 4 \times 1 \times - 18 } ) \div 2 \times 1 \\ x = (6 + \sqrt{36 - ( - 72)} ) \div 2 \\ x = (6 + \sqrt{36 + 72} ) \div 2 \\ x = (6 + \sqrt{108} ) \div 2 \\ x = (6 + 10.3923) \div 2 \\ x = 16.3923 \div 2 \\ x = 8.19615$

and

$x = ( - ( - 6) - \sqrt{ { - 6}^{2} - 4 \times 1 \times - 18 } ) \div 2 \times 1 \\ x = (6 - \sqrt{36 - ( - 72)} ) \div 2 \\ x = (6 - \sqrt{36 + 72} ) \div 2 \\ x = (6 - \sqrt{108} ) \div 2 \\ x = (6 - 10.3923) \div 2 \\ x = - 4.3923 \div 2 \\ x = - 2.19615$

thus the two roots are 8.19615 and -2.19615

please please mark it as brainliest

#BAL

#answer with quality