Question

solve for x : x^2 -(2b-1)x +(b^2-b-20)=0

Answer 1

$\frac{(2b - 1) - \sqrt{ {(2b - 1)}^{2} - 4 ( {b}^{2} - b - 20)}}{2}$
$4 {b}^{2} + 1 - 4b - 4 {b}^{2} + 4b + 80$
(2b-1-9)/2
(2b-10) /2
x=b-5 and b-4
putting value of b in the equation
you will get final answer