solve for x : x^2-9/x+3=4/7
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Answered by
215
Given problem is : ( x² - 9) / (x + 3) = 4 /7
Cross multiply the terms:
7 x² - 7*9 = 4x + 4*3
7 x² - 4 x - 75 = 0
7 * 3 * 5 * 5 = 21 * 25 difference is 4
7 x² - 25 x + 21 x - 75 = 0
x (7x - 25) + 3 (7 x - 25) = 0
(x + 3) (7 x - 25) = 0
x = -3 or x = 25/7
Cross multiply the terms:
7 x² - 7*9 = 4x + 4*3
7 x² - 4 x - 75 = 0
7 * 3 * 5 * 5 = 21 * 25 difference is 4
7 x² - 25 x + 21 x - 75 = 0
x (7x - 25) + 3 (7 x - 25) = 0
(x + 3) (7 x - 25) = 0
x = -3 or x = 25/7
kvnmurty:
:-)
Answered by
167
Heya user,
---> [ x² - 9 ] / [ x + 3 ] = 4 / 7
==> 7[ x + 3 ][ x - 3 ] = 4 [ x + 3 ]
==> 7 [ x + 3 ][ x - 3 ] - 4 [ x + 3 ] = 0
==> [ x + 3 ] [ 7x - 21 - 4 ] = 0
==> [ x + 3 ] = 0 ------------ or ----------- [ 7x - 25 ] = 0
==> x = -3 or 25/7 <--- Desired Result...
---> [ x² - 9 ] / [ x + 3 ] = 4 / 7
==> 7[ x + 3 ][ x - 3 ] = 4 [ x + 3 ]
==> 7 [ x + 3 ][ x - 3 ] - 4 [ x + 3 ] = 0
==> [ x + 3 ] [ 7x - 21 - 4 ] = 0
==> [ x + 3 ] = 0 ------------ or ----------- [ 7x - 25 ] = 0
==> x = -3 or 25/7 <--- Desired Result...
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