Math, asked by kaurbhupinder2dec, 7 months ago

Solve for x : x
^2 (x-1 )(x-2) ≤ 0 ​

Answers

Answered by sanchitachauhan241
0

 \bf  \huge  \boxed{Answer}

 \bf \: {Let's  \: solve \:  your  \: inequality \:  step-by-step.}

 \bf \:  {x}^{2} (x - 1)(x - 2) \:   ≤ \: 0

 \bf \:  {x}^{4}  -  {3x}^{3} +  {2x}^{2}   ≤ \: 0

 \bf \: Let's \:  find \:  the  \: critical \:  points \:  of  \: the \:  inequality.

  \bf \: {x}^{4}  -   {3x}^{3}  +  {2x}^{2}  = 0

 \bf \:  {x}^{2} (x - 1)(x - 2) \:  = 0  \bigg(Factor \:  left \:  side \:  of  \: equation  \bigg)

 \bf \:  {x}^{2}  = 0  \:  \: \:  or  \:  \: \: x - 1 \:  =  \: 0 \:  \ \:  \: or \:  \: x  - 2 \:  =  \: 0 \:  \bigg(set \: factors \:  equal  \: to \:  0 \bigg)

 \bf \: x=0 or x=1 or x=2

 \bf \: Check  \bf \: intervals    \bf \:  in  \bf \: between  \bf \: critical   \bf \: points .  \bigg( \bf \: Test   \: values  \bf \: in  \bf \: the  \bf \:  intervals   \bf \: to  \bf \: see   \bf \: if  \bf \:   \bf \: they  \bf \: work. \bigg)

 \bf \: x \: ≤ \: 0 \bigg(Doesn't  \: work  \: in \:  original \:  inequality \bigg)

 \bf \: 0≤x≤1 \bigg(Doesn't \:  work \:  in \:  original  \: inequality \bigg)

 \bf \: 1≤x≤2 \bigg(Works \:  in  \: original \:  inequality \bigg)

 \bf \: x≥2 \bigg(Doesn't  \: work  \: in  \: original \:  inequality \bigg)

 \bf  \underline {Answer:}

 \bf \: 1≤x≤2 or x=0

 \bf \underline  { Hope  \: it's \:  helps \:  you }

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