Math, asked by anurag57061, 6 months ago

solve for x ( x+2)(x+3)+(x-3) (x-2) =0​

Answers

Answered by aleena1962
1

Answer:

1/3

step- by - step explanation:

4x+2x+3-3-2=0

6x-2=0

6x=2

x=2/6

= 1/3

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Answered by Anonymous
58

Answer:

Given:

  • (x + 2) (x + 3) + (x - 3) (x - 2) = 0.

Find:

  • Find the value of x.

Calculations:

⇢ (x + 2) (x + 3) + (x - 3) (x - 2) = 0.

Simplify both sides:

⇢ 2x² + 12 = 0.

Subtracting 12 from both the sides:

⇢ 2x² + 12 - 12 = 0 - 12.

⇢ 2x² = -12.

Now dividing 2 on both the sides:

⇢ 2x²/2 = -12/2.

⇢ x² = -6.

Taking square roots, we get:

⇢ x = ± √-6.

Note:

  • I have solved this equation using the square root method.
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