Question

Solve for x: x^2+x-(a^2+3a+2)=0

Answer 1

Step-by-step explanation:

ANSWER

Given quadratic equation

(a2−a−2)x2+(a2−4)x+a2−3a+2=0

We know that Ax2+Bx+C=0 will have more than two solution, if

A=B=C=0

So, a2−a−2=0

⇒a=2,−1

a2−4=0

⇒a=−2,2

a2−3a+2=0

⇒(a−1)(a−2)=0

⇒a=1,2

Common value of a=2.