solve for 'x'.
x(2x+1)(x-2)(2x-3)= 63
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Step-by-step explanation:
Given Equation is x(2x + 1)(x - 2)(2x - 3) = 63
⇒ x(2x²- 3x - 2)(2x - 3) = 63
⇒ x(4x³ - 12x² + 5x + 6) = 63
⇒ 4x⁴ - 12x³ + 5x² + 6x = 63
⇒ 4x⁴ - 12x³ + 5x² + 6x - 63 = 0
⇒ 4x⁴ + 5x² + 21x - 12x³ - 15x - 63 = 0
⇒ x(4x³ + 5x + 21) - 3(4x³ + 5x + 21) = 0
⇒ (x - 3)(4x³ + 5x + 21) = 0
⇒ (x - 3)(2x + 3)(4x³ + 5x + 21) = 0
⇒ x = 3, -3/2, (3/4) ± i(√47/4)
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