Math, asked by AKDXB26, 8 months ago

solve for X; x square - root 2 +1 multiplied by X + root 2 = 0

Answers

Answered by Anonymous
0

Answer:

\large\boxed{\sf{x = - \sqrt{2}, \: \pm\sqrt{\sqrt{2}-1}}}

Step-by-step explanation:

( {x}^{2}  -  \sqrt{2}  + 1)(x +  \sqrt{2} ) = 0 \\  \\

Clearly, we have two conditions:

(1)( {x}^{2}  -  \sqrt{2}  + 1) = 0 \\  \\  =  >  {x}^{2}  =  \sqrt{2}  - 1 \\  \\  =  > x =   \pm\sqrt{ \sqrt{2}  - 1}

(2)(x +  \sqrt{2} ) = 0 \\  \\  =  > x =  -  \sqrt{2}

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