Question

The co – ordinates of the point which is equidistant from the three vertices
A(0, 2y), O(0,0) and B(2x,0) of the ΔAOB if as shown in the figure is,
A) (x,y) B) (y,x), C) x/y , y/x D)x/2 , y/,2

Answer 1

Answer:

A) (x,y)

I hope this helps you.  Have a good day!!

Step-by-step explanation:

To be equidistant from the points (0, 2y) and (0,0), it must be on the perpendicular bisector of this segment.  So it must have y-coordinate equal to "y"  (because that's half way between 2y and 0).

Already, only answer (A) satisfies this, but it's worth checking further....

To be equidistant from the points (2x, 0) and (0,0), it must be on the perpendicular bisector of this segment.  So it must have x-coordinate equal to "x" (because that's half way between 2x and 0).

Yep, it's (A) all right!