Question

Solve for x : x2 + 3x + 9 = 0.​

Answer 1

Step-by-step explanation:

• x² + 3x + 9 = 0
• Here a = 1 , b = 3 , c = 9
• b² - 4ac = ( 3 )² - 4 × 1 × 9
• = 9 - 36
• = -25
• But b² - 4ac is negative.
• Hence roots are not real.

Answer 2

Answer:

The roots of the equation x² + 3x + 9 = 0 are $x=[\frac{-3-\sqrt{-27}}{2},\frac{-3+\sqrt{-27}}{2}]$.

Step-by-step explanation:

The quadratic equation provided is: x² + 3x + 9 = 0.

The roots of a quadratic equation are:

$x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}$

Here a = 1, b = 3 and c = 9.

Compute the roots of the equation as follows:

$x=\frac{-3\pm\sqrt{3^{2}-(4\times1\times9)}}{2\times1}=\frac{-3\pm\sqrt{-27}}{2}$

Thus, the roots of the equation x² + 3x + 9 = 0 are $x=[\frac{-3-\sqrt{-27}}{2},\frac{-3+\sqrt{-27}}{2}]$.