Question

Solve for x

x² + ( 4 - 3y ) x - 12y = 0 ​

Answer 1

Question:

Solve for x:

x2 + (4 – 3y)x – 12y = 0

Solution:

Here, x2 + 4x – 3xy – 12y = 0

⟹ x(x + 4) - 3y(x + 4) = 0

or, (x + 4) (x – 3y) = 0

⟹ x + 4 = 0 or x – 3y = 0

⟹ x = -4 or x = 3y

Therefore, x = -4 or x = 3y

Answer 2

Answer:

x^2+4x-3xy-12y

x^2+4x-3xy=12y

x(x+4-3y)=12y

x=12y/x+4-3y