Solve for x, y: 3x - 2y =6
X/3 - y/6 =1/2
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3x - 2y = 6 -----(Eq.1)
x/3 - y/6 = 1/2
Taking LCM = 6
(2x - y)/6 = 1/2
Cross multuplication
2(2x - y) = 1 × 6
4x - 2y = 6 ----(Eq.2)
3x - 2y = 6
4x - 2y = 6
- + = -
........................
-x = 0
x = 0
Substituting the value of x in eq. 1
3x - 2y = 6
3(0) - 2y = 6
0 - 2y = 6
2y = -6
y = -3
x = 0 and y= -3
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