Solve for x,y,z,
x+y=4
x+y+y+z+z+x=6
2x+2y+2z=6
x+y+z=3
Answers
Answered by
1
x+y=4
x+y+z=3
4+z=3 as x+y=4
z=-1
Value of x and y cannot be determined as each given term leads us to the same term i.e. x+y=4
There should be one more term given to determine their values. Otherwise, according to this question, x and y have infinite number of values.
z=-1
x+y+z=3
4+z=3 as x+y=4
z=-1
Value of x and y cannot be determined as each given term leads us to the same term i.e. x+y=4
There should be one more term given to determine their values. Otherwise, according to this question, x and y have infinite number of values.
z=-1
Answered by
1
x+y = 4
x+y+z = 3
4+z = 3
z = 3-4
z = -1
x+y = 4
Though we substitute the value of z in any equation, we can not determine the exact values of x and y.
There are infinite number of solutions for values of x and y.
So, in the equation,
x+y = 4
must be given other variable 'z'.
Hope it helps
x+y+z = 3
4+z = 3
z = 3-4
z = -1
x+y = 4
Though we substitute the value of z in any equation, we can not determine the exact values of x and y.
There are infinite number of solutions for values of x and y.
So, in the equation,
x+y = 4
must be given other variable 'z'.
Hope it helps
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