Solve for z. −4 ≤ 11 − 3z a. z ≥ 5 b. z ≤ 5 c. z ≤ −5 d. z ≥ −5
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- 4 ≤ 11 - 3z ; Solve for z
In these types of questions, we simply use "≤" as an equal sign when solving.
Subtract 11 from both sides.
-4 - 11 ≤ -3z
Simplify.
-15 ≤ -3z
Divide both sides by -3.
{Due to the fact that we divided both sides by a negative, we have to change the symbol.
-15 / -3 ≥ -3z / -3
Simplify.
5 ≥ z
So, z ≥ 5
Our answer is : a. z ≥ 5
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