Question

solve given equation x^2+x-(a+2)(a-1)=0
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Answer 1

Answer:

Given x2+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=2a−b±b2−4ac=2(1)−1±12−4{(a+2)(a+1)}=2−1±1−4{−(a2+3a+2)

x=2−1±1+4a2+12a+8=2−1±4a2+12a+9=2−1±(2a+3)2=2−1±(2a+3)

∴x=2−1+2a+3 and x=2−1−2a−3∴

Answer 2

Answer:

Given x2+x−(a+2)(a+1)=0, Here, a = 1, b = 1, c = -(a + 2)(a + 1)

x=2a−b±b2−4ac=2(1)−1±12−4{(a+2)(a+1)}=2−1±1−4{−(a2+3a+2)

x=2−1±1+4a2+12a+8=2−1±4a2+12a+9=2−1±(2a+3)2=2−1±(2a+3)

∴x=2−1+2a+3 and x=2−1−2a−3∴

Step-by-step explanation:

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