Solve graphically , 3x + y -12 = 0 and x – 3y + 6 = 0. Shade the region bounded by the lines and x- axis.Also, find the area of shaded region.
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So we have, 2x+3y=4 and x-y+3=0
Now 2x+3y=4
= x= 4−3y2
When y=0 then, x=2
When y=2 then, x=-1
Thus, we have the following table giving points on the line x+y=4
X -1 2
Y 2 0
Now , x-y+3=0
=x=y-3
When y=3, then x=0
When y=4, then x= 1
Thus, we have the following table giving points on the line x-y+3=0
X 0 1
Y 3 4
Graph of the equation 2x+3y=4 and x-y+3=0
8
Clearly two lines intersect at (-1, 2)
Hence x=-1 and y=2 is the solution of the given system of equations.
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