solve graphically the pair of linear equation and write the coordinates of the vertices of the Triangle formed by these two lines with x-axis 3 X + Y - 3 =0 ; 2x - y + 8 = 0
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Sol:
2x + 5y = 12
We have,
x + y = 3
When y = 0 we have x =3
When x= 0 we have y =3
Thus we have the following table giving points on the line x+y =3
X 0 3
Y 3 0
Now, 2+5y= 12
= y = 12−2x5
When x= 1, we have
= y = 12−2(1)5 = 4
Thus we have the following table giving points on the line 2x+5y=12
X 1 -4
Y 2 4
Graph of the equation x+y =3 and 2x+5y=12 is
Clearly two lines intersect at a point P (1,2)
Hence x= 1 and y = 2
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swastimishra1911:
that's not my question
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