Question

X + 2 is a factor of mx^3 + nx^2+x-6 .It eaves the remainder 4 when divided by x- 2 find M and n​

Answer 1

Mx3+nx2+x-6 has (x+2) as a factor and it leaves a remained of 4 divide by x-2. 3(11+3m+n)=3(1) 11+3m+n=1, 3m+n=-10.

Name it as eq.2, On substracting eq.1 and 2, we get:-m=3, m=-3. Put this value of m in any eq.1 or 2, to get n=-1. So we get n=-1 as the answer by dividing with 4.

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