Question

Solve graphically:x + 2y - 3; 4x + 3y - 2​

Answer 1

EXPLANATION.

⇒ x + 2y - 3 = 0. - - - - - (1).

⇒ 4x + 3y - 2 = 0. - - - - - (2).

As we know that,

From equation (1), we get.

⇒ x + 2y - 3 = 0. - - - - - (1).

Put the value of x = 0 in equation, we get.

⇒ (0) + 2y - 3 = 0.

⇒ 2y = 3.

⇒ y = 3/2.

⇒ y = 1.5.

Their Co-ordinates = (0,1.5).

Put the value of y = 0 in equation, we get.

⇒ x + 2(0) - 3 = 0.

⇒ x - 3 = 0.

⇒ x = 3.

Their Co-ordinates = (3,0).

From equation (2), we get.

⇒ 4x + 3y - 2 = 0. - - - - - (2).

Put the value of x = 0 in equation, we get.

⇒ 4(0) + 3y - 2 = 0.

⇒ 3y - 2 = 0.

⇒ 3y = 2.

⇒ y = 2/3.

⇒ y = 0.66.

Their Co-ordinates = (0,0.66).

Put the value of y = 0 in equation, we get.

⇒ 4x + 3(0) - 2 = 0.

⇒ 4x - 2 = 0.

⇒ 4x = 2.

⇒ x = 2/4.

⇒ x = 0.5.

Their Co-ordinates = (0.5,0).

Both curves intersects at a point = (-1,2).

Answer 2

$\large\bf\underline\red{Answer \: :-}$

Given equations :

x + 2y - 3; 4x + 3y - 2

By first,

$\sf\purple{x + 2y - 3 = 0 ---(1) }$

By second,

$\sf\purple{4x + 3y - 2 = 0 ---(2) }$

First equation x + 2y - 3 = 0

Put x = 0

→ 0 + 2y - 3 = 0

→ 2y = 3

→ y = 3/2

→ y = 1.5

$\sf{(x,y) = (0,1.5)}$

Put x = 1

→ 1 + 2y - 3 = 0

→ 2y = 3 - 1

→ 2y = 2

→ y = 2/2

→ y = 1

$\sf{(x,y) = (1,1)}$

Second equation 4x + 3y - 2 = 0

Put y = 0

→ 4x + 3(0) - 2 = 0

→ 4x = 2

→ x = 2/4

→ x = 0.5

$\sf{(x,y) = (0.5,0)}$

Put y = 1

→ 4x + 3(1) - 2 = 0

→ 4x + 3 = 2

→ 4x = 2 - 3

→ 4x = - 1

→ x = - 1 / 4

→ x = - 0.25

$\sf{(x,y) = (0.25,1)}$

$\bigstar \: \sf \underline\red{Intersection \: point = \: ( -1 , 2)}$

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