solve he question number 9
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9) p(x)=5x^4-5x³-33x²+3x+18=0
two of the zeroes are √3/5 and -√3/5
(x-√3/5)*(x+√3/5)
x²-3/5 or 5x²-3 will be a factor of p(x)
by long division we get x²-x-6
x²-x-6=0
(x²-3x)(+2x-6)=0
x(x-3)+2(x-3)=0
(x+2)(x-3)=0
x=-2,3
so,-2 and 3 are the two other zeroes of the p(x)
hope it helps please mark as brainliest
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harsh3887:
solve question number 10
i know how to solve it the problem is i don't know how to take a screen shot
you assume some value of x and then find y and plot the two lines then you will see that a triangle is formed then see the vertices then write them in your notebook. soory cause i was not able to help
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