Math, asked by juttuc4, 1 year ago

SOLVE i) (-2015)^3+(-2016)^3+(4031)^3
ii)  a(b-c)^2+b(c-a)^2+c(a-b)^2+8abc

Answers

Answered by kvnmurty
3
1)
 -2015^3-2016^3+4031^3\\\\=-(2015^3+2016^3)+4031^3\\\\=-(2015+2016)(2015^2-2015*2016+2016^2)+4031[2015+2016]^2\\\\-4031[ 2015^2-2015*2016+2016^2]\\.\ \ \ \ \ +4031[ 2015^2+2*2015*2016+2016^2]\\\\=4031*3*2015*2016\\\\=49,124,668,320\\

2)
a(b-c)^2+b(c-a)^2+c(a-b)^2+8abc\\\\=ab^2+ac^2-2abc+bc^2+ba^2-2abc+c(a-b)^2+8abc\\\\=ab(a+b)+c^2(a+b)+4abc+c(a-b)^2\\\\=(a+b)(ab+c^2)+4abc+ca^2+cb^2-2abc\\\\=(a+b)(ab+c^2)+c(a+b)^2\\\\(a+b)[ab+c^2+ca+cb]\\\\=(a+b)(b+c)(c+a)\\


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