Math, asked by parabjotparavjot, 4 months ago

Solve I) 3(n-5)=21
II) 6z+10= -2​

Answers

Answered by Anonymous
1

Answer:

1.  3[n-5] = 21

    3n -15 = 21

    3n = 21 +15

     3n =36

      n=36/3

       n= 12

2. 6z +10 =-2

   6z = -2 -10

   6z = -12

   z  =   -12 / 6

   z = -2

Answered by wwwkumarimanika1978h
3

Answer:

3(n-5) = 21

=3n- 15 = 21

=3n = 21+15

=3n = 36

=n = 36/3

n= 12 Ans

6z+10 = -2

6z = -2-10

6z = -12

z = -12/6

z = -2 Ans

explanation:

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