solve i, ii, ii I, iv
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Angle DAC=angleBAC Angle DAC= Angle BCA And AZ is the common line So ∆BAC and DAC are congruent (ii) From here you can write down the equal parta of the two ∆s (i) As these two ∆s are congruent so AB=AD (iii) and CD=CB(iv)
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1. In triangle BAC and triangle DAC , we have ,
angle DAC = angle BAC (GIVEN) (A)
AC = AC (COMMON) (S)
angle DCA= angle BCA (Given) (A)
2.From the above equal parts , it is proved that triangle BAC is congruent to triangle DAC by ASA criteria.
3. Now , by CPCT , we have , AB=AD.
4. Now , by CPCT , we have , CD=CB.
angle DAC = angle BAC (GIVEN) (A)
AC = AC (COMMON) (S)
angle DCA= angle BCA (Given) (A)
2.From the above equal parts , it is proved that triangle BAC is congruent to triangle DAC by ASA criteria.
3. Now , by CPCT , we have , AB=AD.
4. Now , by CPCT , we have , CD=CB.
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