Solve
i²+i⁴ =?
where i is iota.
Answers
Answered by
4
i = iota =√-1
i²=(√-1)²=-1
i⁴=(i²)² = (-1)² = 1
So answer will be
= -1+1
=0
i²=(√-1)²=-1
i⁴=(i²)² = (-1)² = 1
So answer will be
= -1+1
=0
Answered by
2
heya ...
here is ur answer..
iota--Iota is a greek letter which is widely used in mathematics to denote the imaginary part of a complex number.
i = iota =√-1
i²=(√-1)²=-1
i⁴=(i²)² = (-1)² = 1
So answer will be
= -1+1
=0
TYSM==@Gozmit
here is ur answer..
iota--Iota is a greek letter which is widely used in mathematics to denote the imaginary part of a complex number.
i = iota =√-1
i²=(√-1)²=-1
i⁴=(i²)² = (-1)² = 1
So answer will be
= -1+1
=0
TYSM==@Gozmit
pritamSingh666:
Lekin maine report to kar diya tha pahle hi. Now moderators will decide.
Moderators have two eyes, If you're happy. so now i am approving this answer :-)
Good
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