Question

Solve if possible !
kindly mention the process

Topic : Friction
Standerd : 11th

Answer 1

here's your answer...
f=uk×N
=1/2√3×mg
=1/2√3×√3×10
=10/2
=5N

so the max. friction that can act on the block is 5N ....,if you want to keep the block stationary then the force must be equal to friction

f=F cos theta (component of force in horizontal direction)
f=F cos 60°
5=F×1/2
thus,F=5×2=10N

(note:-f= friction,F=applied force)

Answer 2

⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐

Hello brother your answer is given in the attachment

[ Note : F cos60° - fr = 0 ]

And Fr = umg - F sin60°

This equation will be used here

If any problem tell me

⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐

@DrSM

Jai bajarang bali