Question

Solve
If $f(x)=\frac{x^{3}+1}{x^{2}+1}$, find f(-3), f(-1)

Answer 1

hope it will helpful

Answer 2

Solution :

Given $f(x)=\frac{x^{3}+1}{x^{2}+1}$

Now ,

i ) $f(-3)=\frac{(-3)^{3}+1}{(-3)^{2}+1}$

= $\frac{(-27+1)}{9+1}$

= $\frac{(-26)}{10}$
=$\frac{-13/5}$
ii)$f(-1)=\frac{(-1)^{3}+1}{(-1)^{2}+1}$

= $\frac{(-1+1)}{1+1}$
After cancellation, we get
= 0
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