Math, asked by surabhisaraf3109, 1 year ago

Write the following relations as sets of ordered pairs
i) {(x, y) / y = 3x, x ∈ {1, 2, 3}, y ∈ {3, 6, 9, 12}}
ii) {(x, y) / y > x+1, x=1, 2 and y = 2, 4, 6}
iii) {(x, y) / x+y = 3, x, y ∈ (0, 1, 2, 3)}

Answers

Answered by VEDULAKRISHNACHAITAN
11

Answer:

{ (1, 3), (2, 6), (3, 9), (4, 12)}

{( 1, 4), (1, 6), (2, 4), (2, 6)}

{(0, 3), (1, 2), (2, 1), (3, 0)}

Step-by-step explanation:

Hi,

i) {(x, y) / y = 3x, x ∈ {1, 2, 3}, y ∈ {3, 6, 9, 12}}

Here , we need to chose all ordered pairs (x, y)

for all x = {1, 2, 3} , such that y = 3x relation

= { (1, 3), (2, 6), (3, 9), (4, 12)}

ii){(x, y) / y > x+1, x=1, 2 and y = 2, 4, 6}

Here, we need chose all ordered pairs such (x, y) such

that y > x+ 1 for all x = {1, 2}

= {( 1, 4), (1, 6), (2, 4), (2, 6)}

iii) {(x, y) / x+y = 3, x, y ∈ (0, 1, 2, 3)}

Here, we will chose all ordered pairs (x, y) satisfying

x + y = 3 for all x = {0, 1, 2, 3}

= {(0, 3), (1, 2), (2, 1), (3, 0)}

Hope, it helps !


Answered by khan1258asim
0

Answer:

here is the answer

hope its help

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