Write the following relations as sets of ordered pairs
i) {(x, y) / y = 3x, x ∈ {1, 2, 3}, y ∈ {3, 6, 9, 12}}
ii) {(x, y) / y > x+1, x=1, 2 and y = 2, 4, 6}
iii) {(x, y) / x+y = 3, x, y ∈ (0, 1, 2, 3)}
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Answer:
{ (1, 3), (2, 6), (3, 9), (4, 12)}
{( 1, 4), (1, 6), (2, 4), (2, 6)}
{(0, 3), (1, 2), (2, 1), (3, 0)}
Step-by-step explanation:
Hi,
i) {(x, y) / y = 3x, x ∈ {1, 2, 3}, y ∈ {3, 6, 9, 12}}
Here , we need to chose all ordered pairs (x, y)
for all x = {1, 2, 3} , such that y = 3x relation
= { (1, 3), (2, 6), (3, 9), (4, 12)}
ii){(x, y) / y > x+1, x=1, 2 and y = 2, 4, 6}
Here, we need chose all ordered pairs such (x, y) such
that y > x+ 1 for all x = {1, 2}
= {( 1, 4), (1, 6), (2, 4), (2, 6)}
iii) {(x, y) / x+y = 3, x, y ∈ (0, 1, 2, 3)}
Here, we will chose all ordered pairs (x, y) satisfying
x + y = 3 for all x = {0, 1, 2, 3}
= {(0, 3), (1, 2), (2, 1), (3, 0)}
Hope, it helps !
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Answer:
here is the answer
hope its help
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