Math, asked by saroj79, 10 months ago

solve if u can..... ​

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Answered by IamIronMan0
1

Answer:

 \frac{{ \sin }^3{x}  +  \cos^3x  }{ \sin(x )  + \cos(x)  }   \\ \\ =  \frac{{( \sin(x )  + \cos(x)) ( \sin }^2{x}  +  \cos^2x   -  \sin(x)  \cos(x) )}{ \sin(x)  +  \cos(x) }  \\  \\  = 1 -  \sin(x)  \cos(x)

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