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If x (3/2)^2 *(2/3)^-4
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Answered by
2
HEY!!
= (3/2)2*(3/2)4
Using the first law of exponents:-
am *an=a(m+n)
= (3/2)2*(3/2)4
= (3/2)2+4
= (3/2)6
Using the identity (a/b)m=(am/bm):-
= 36/26
= 729/64
= (3/2)2*(3/2)4
Using the first law of exponents:-
am *an=a(m+n)
= (3/2)2*(3/2)4
= (3/2)2+4
= (3/2)6
Using the identity (a/b)m=(am/bm):-
= 36/26
= 729/64
Answered by
5
Heya ✋
Let see your answer !!!
(3/2)^2 × (2/3)^-4
= (3/2)^2 × (3/2)^4
= (3/2)^2 + 4
= (3/2)^6
=729/64
Thanks :))))
Let see your answer !!!
(3/2)^2 × (2/3)^-4
= (3/2)^2 × (3/2)^4
= (3/2)^2 + 4
= (3/2)^6
=729/64
Thanks :))))
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