Question

solve if you know no Google no spaming​

Answer 1

GIVEN:

Two resistors are 4ohm and 6ohm are in parallel combination

First find : R equivalent .

In parallel combination we use

$\boxed{ \green{ \frac{1}{r} = \frac{1}{r1} + \frac{1}{r2} ....}}$

we get ,

$\boxed{ \bold{2.4 \: ohm \: }}$

Now find :

◆Power supplied by the battery :

Given : V=6v

and we get R(eq) = 2.4ohm

Use the formula:

$\boxed{ \red{p = \frac{ {v}^{2} }{r} }}$

we get 15 watt .

Now , we know that in parallel combination

the voltage across the resistor is same .

◆Power dissipated by 4 and 6 ohm is

$\boxed{ \bold{9 \: watt} }\: \\ and \\ \boxed{ \bold{6 \: watt}}$

soln refers to the attachment

Answer 2

Question :--

• Power supplied by the battery
• the power dissipated in each resistor .

Given :----

• Resistor A have resistance = 4 ohm = R1
• Resisotor B have resistance = 6 ohm = R2

Solution :-----

Total Resistance = 1/R = 1/R1 + 1/R2

putting values we get,

1/R = 1/4 + 1/6

1/R = 3/12 + 2/12

1/R = 5/12

R = 12/5 = 2.4 ohm...

(i) So, Power supplied by battery

P = V^2/R

P = (6*6)/2.4 = 36/2.4 = 15 Watt

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(ii) Power dissipated in R1

P = V^2/R

P = (6*6)/4 = 36/4 = 9 Watt

[ P.d is same across every resistor in Parallel combination ]

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(iii) Power disspitated in R2

P = 36/6 = 6 Watt..

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(Hope it helps you)