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16
Given,
length = 80cm
Breadth = 35cm
⟹ Perimeter of Rectangle = 2(Length + breadth}
⟹ 2(80+35)
⟹ 2(115)m
⟹ = 230m
⟹ Area of Rectangular field= lenght × breadth
⟹ = 80×35
⟹ = 2800 m²
Cost of levelling = Rs. 4.5/m²
⟹ = 4.5×2800
⟹ = 12,600 rs.
The boy walks at the rate of 1.5m /sec.
The boy will walk across the perimeter of the field.
⟹ (3 rounds) 3× 230
⟹ = 690 m
Total Distance = 690 m
⟹ Speed = Distance /time
⟹ Time = 690/1.5
⟹ = 460 seconds
⟹ = 7.6Minutes
length = 80cm
Breadth = 35cm
⟹ Perimeter of Rectangle = 2(Length + breadth}
⟹ 2(80+35)
⟹ 2(115)m
⟹ = 230m
⟹ Area of Rectangular field= lenght × breadth
⟹ = 80×35
⟹ = 2800 m²
Cost of levelling = Rs. 4.5/m²
⟹ = 4.5×2800
⟹ = 12,600 rs.
The boy walks at the rate of 1.5m /sec.
The boy will walk across the perimeter of the field.
⟹ (3 rounds) 3× 230
⟹ = 690 m
Total Distance = 690 m
⟹ Speed = Distance /time
⟹ Time = 690/1.5
⟹ = 460 seconds
⟹ = 7.6Minutes
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Answered by
10
Length of playground = 80 m.
Breadth of playground = 35 m.
Area of playground = length×breadth
=80×35
= 2800 m^2
Cost of levelling 1 m^2 = ₹4.50
Cost of levelling 2800 m^2 = ₹4.50×2800
__________________________
2) Perimeter of playground = 2(l+b)
= 2(80+35)
=2×115
=230 m
Speed of boy = 1.5 m/sec
Distance covered in 1 round = perimeter of playground
=230 m
Distance covered in 3 rounds = 3×230
= 690 m
Time taken = distance/speed
=690/1.5
Breadth of playground = 35 m.
Area of playground = length×breadth
=80×35
= 2800 m^2
Cost of levelling 1 m^2 = ₹4.50
Cost of levelling 2800 m^2 = ₹4.50×2800
__________________________
2) Perimeter of playground = 2(l+b)
= 2(80+35)
=2×115
=230 m
Speed of boy = 1.5 m/sec
Distance covered in 1 round = perimeter of playground
=230 m
Distance covered in 3 rounds = 3×230
= 690 m
Time taken = distance/speed
=690/1.5
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