CBSE BOARD XII, asked by Norensingh, 1 year ago

Solve is f ast

Please fast!​

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Answered by Anonymous
16
Given,

length = 80cm

Breadth = 35cm

\implies ⟹ Perimeter of Rectangle = 2(Length + breadth}

\implies⟹ 2(80+35)

\implies⟹ 2(115)m

\implies⟹ = 230m

\implies⟹ Area of Rectangular field= lenght × breadth

\implies⟹ = 80×35

\implies⟹ = 2800 m²

Cost of levelling = Rs. 4.5/m²

\implies⟹ = 4.5×2800

\implies⟹ = 12,600 rs.

The boy walks at the rate of 1.5m /sec.

The boy will walk across the perimeter of the field.

\implies⟹ (3 rounds) 3× 230

\implies⟹ = 690 m

Total Distance = 690 m

\implies⟹ Speed = Distance /time

\implies⟹ Time = 690/1.5

\implies⟹ = 460 seconds

\implies⟹ = 7.6Minutes

\bf{\textcolor{blue}{\colorbox{lime}{Answer : [1] 12,600 Rs.}}}


\bf{\textcolor{blue}{\colorbox{lime}{Answer : [2] Time taken = 460sec ~7.6 minutes.}}}

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Answered by SillySam
10
Length of playground = 80 m.

Breadth of playground = 35 m.

Area of playground = length×breadth

=80×35

= 2800 m^2

Cost of levelling 1 m^2 = ₹4.50

Cost of levelling 2800 m^2 = ₹4.50×2800

\bf{= Rs \:12600 }

__________________________

2) Perimeter of playground = 2(l+b)

= 2(80+35)

=2×115

=230 m

Speed of boy = 1.5 m/sec

Distance covered in 1 round = perimeter of playground

=230 m

Distance covered in 3 rounds = 3×230

= 690 m

Time taken = distance/speed

=690/1.5

\bf{=460\: sec }

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