Question

solve it................​

Answer 1

Answer:

p(3)+3(3)+r=0

3p+9+r=0...............(1)

in x= 1/3

p(1/3)+3(1/3)+r=0

p/3+1+r=0.............(2)

from 1 and 2

(1)=(2)

3p+9+r=p/3+1+r

3p-3/p=-8

3p*p-3=-8p

3p*p+8p-3=0

3p*p+9p-p-3=0

3p(p+3)-1(p+3)=0

(3p-1)(p+3)=0

p=-3 or 1/3

now p=-3 in (1)

3(-3)+9+r=0

-9+9+r=0

r=0